- Quiz
- Biconditional Proofs
A.
- ~P>R
- (P>~Q)>~R
- P>~Q /:. P<>~Q
B.
- Unless you BRUSH your teeth and SHOWER you shouldn't WRESTLE with me.
- If you neither did the HOMEWORK nor came to OFFICE hours you're going to have a BAD time.
- You should PANIC only if you don't know how to do MODUS ponens and modus TOLLENS.
Setting Up Proofs with Biconditional (Biconditional Strategy)
You will use this method anytime a biconditional is the bottom line unjustified line of your proof. Think of <> as & for two >s. In other words, I going to have to do two proofs: one proof for one direction and one for the other.
Suppose you have to solve for P<>Q. P<>Q is logically equivalent to P>Q & Q>P. This means in order to prove P<>Q I'm going to have to do two proofs: one for P>Q and one for Q>P then I can put them together using <>Int.
Step 1: Write P<>Q at the bottom of your proof.
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x. P<>Q
Step 2: I know that P<>Q is the same as P>Q and Q>P. Scan the given assumptions above to see if I'm given either of the conditionals. If I'm not given any then I'm going to set up two proofs: one for P>Q and one for Q>P. If one of the two conditionals is given to me in the assumptions then I only need to set up a proof for the conditional not given in the assumptions.
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e. Q>P
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m. P>Q
x. P<>Q <>Int e, m
Step 3: Now that I've set up my proof I go about independently solving for both P>Q and Q>P beginning with CP as we've learned from previous lessons.
a. Q ACP
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d. P ____
e. Q>P CP a, d
f. P ACP
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l. Q ____
m. P>Q CP f, l
x. P<>Q <>Int. e, m.
Proofs with <> + MP, MT, DN, &Int, &Elim, CP
A.
- ~P>R
- (P>~Q)>~R
- P>~Q /:. P<>~Q
B.
- P&~Q /:. P<>~Q
C.
- ~(C&~B)>~A /:. (A&~B)<>A
D.
- (S>R)&~R
- (~S>Q)&P
- P>R /:. (P&Q)<>(~S>R)
E.
- (C<>~D)&C
- B<>~A /:. (A>~B)&(C&~D)
F.
- ~S>(~Q&R)
- S>~(P>~Q) /:. ((P>~Q)&R)<>~S
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